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For the flow over a flat plate value of the critical Reynold's Number is 5*10 ⁵

for the Re>5*10 ⁵ the flow is known to be turbulent

and if Re<5*10 ⁵ then the flow is Laminar

In the first row Reynold's number is 54694.17 (> 5*10 ⁵ ) hence the flow is turbulent in this observation

In the second row, Reynold's number is 4600.745 (< 5*10 ⁵ ) hence the flow is Laminar in this observation

In the second row, Reynold's number is 3910.633 (< 5*10 ⁵ ) hence the flow is Laminar in this observation

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Answer.) Keplerian Telescopes 🔭. :

 The Kepler telescope 🔭 as shown in the figure consists of two converging Lens, one is called Objective lens and another is called eyepiece Lens ....

Now it is given that ;

the object is lying in the front focal plane of the first lens

therefore,

magnification m = -fo/fe = -2

Implies , fo ( objective focal length)

= 2 • fe ( eyepiece focal length) ...

image size = m • object size

image size = -2 •5 mm = -1 cm

for normal adjustment Lenght

L = fo + fe = 3 • fe

for calculation and N.A of the objective lens ;

 hence , the numerical aperture NA = 0.159

answer.....

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Anilline derivative

Amide derivative :

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ANSWER:-

​​​​​​

Every employee before opting for a job lays emphasis on few important things such as job profile, compensation to be paid, added benefits to the compensation package. No employee is willing to work for cash alone they expect some extra benefits added to their salary, also known as fringe benefits. An employee would definitely before signing a job offer like to negotiate the salary and benefits. Few questions you would like to ask your employer concerning benefits are:

1. Does the employer pay for insurance coverage? If yes, then how much would be the individual insurance cover/or family coverage?

2. Do I have the option of reviewing the insurance plan options provided by the employer?

3. How must sick time, vacation time or holidays would be provided and from what time period will I start earning these benefits?

4. What would be the pension plans available?

5. If required will the company provide for any training or educational benefits?

The benefits package that you would like to negotiate for yourself would be regarding the insurance cover that the company is providing, moving allowances for projects etc., pension plans according to the need of family at the time of retirement, and all such benefit plans which do not meet your requirement.

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Answer

Draw the rotational mechanical system shown TU) θ1(t) 50 kg-m N-30 N2-100 100 kg-m2 100 N-m/rad 100 N-m-s/rad The torque T(t) is multiplied by 2 as it is reflected by the gear N. with a gear ratio of 2 MT- 00)-333T(0) Calculate the value of equivalent moment of inertia J 50x50x Draw the modify diagram in frequency domain %(100)2 30 555.56 .33 T 2(s) Je 03(s) 555.56 kg-m2 : 100 kg-m2 100 N-m/rad 100 N-m-sec/rad Write the equations of motion. Calculate the equation of motion is written using the formula Sum of Sum of mpedanceS connected to the motion at θ impedances 2between and θ Sum of applied torques at θ 1)

Sum of impedances between 0, and e Sum of impedances connected to the motion at θ Sum of applied torques at 6, Write the equation of motion for 555.56 kg-m 555.56s 6, (s) +1000, (s)-1000, (s) 3.33T (s) (555.56s? +100) (s)-1000, (s)-3.337(s) Write the equation of motion for 100kg-m2. 100s'0 (s)+100se, (s)+1006, (s)-1000, (s)0 -1000, (s)+(100s+100s +100)e (s) 0 Consider the following 4 s02 (s)- 6, se, (s) 03 Rewrite the equations (3) and (4) 555.560, + 1006,-1000, = 3.33T 555.560,-1000, 1000, + 3.33 e,0.180, 0.180 0.006T 1000, +1000 +1000 +10000 1008 100a-1000,-1000,-0

Define the state variables Write the state equations using equations of motion and in terms of state variables Rewrite the equations (5) and (6) Ý, =-0.18x, +0.18x3 + 0.006T 0 t.| |-0.18 0 0.18 0 ||x.| |0.006 0 0 0x 1 0 0 0 0 1 00 -0.18 0 0.18 0 0 0 01 1 0-1 The output equation(y) is 0.006 t, y 3.33 0 0 0ll2 y=[3.33 0 0 01x

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Given problem is a typical mixing problem

Let y(t) is the salt in tank at time t

The water entering has no salt, rate in =0

The thoroughly mixed solution has concentration of 10L/min . The tank has 1119 L of brine with 15 kg of salt

Rate out =( y/1119) kg/ L * 10 L/min = 10 y/ 1119 kg/mim

Hence, differential equation is 

at t=0, y= 15

15= C

c= 15

Therefore, y= 

After 20 minutes, t= 20

y= 12.54496 kg

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ANSWER;

 

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4) Depreciation per annum using straight line = (Cost - Residual Value)/Useful Life

= ($40,000,000 - $40,000)/6 years = $6,660,000 per year

Depreciation Schedule using the straight line method (Amounts in $)

Date	Asset Cost (A)	Depreciation for the year (B)	Accumulated Depreciation (C)	Book Value (A-C)
01/01/19	40,000,000			40,000,000
12/31/19	40,000,000	6,660,000	6,660,000	33,340,000
12/31/20	40,000,000	6,660,000	13,320,000	26,680,000
12/31/21	40,000,000	6,660,000	19,980,000	20,020,000
12/31/22	40,000,000	6,660,000	26,640,000	13,360,000
12/31/23	40,000,000	6,660,000	33,300,000	6,700,000
12/31/24	40,000,000	6,660,000	39,960,000	40,000
Total		39,960,000

5) Depreciation per hour = (Cost - Residual Value)/Useful Life in hours

= ($40,000,000 - $40,000)/24,000 hours = $1,665 per hour

Depreciation Schedule using the straight line method (Amounts in $)

Date	Asset Cost (A)	Depreciation for the year (B)	Accumulated Depreciation (C)	Book Value (A-C)
01/01/19	40,000,000			40,000,000
12/31/19	40,000,000	($1,665*4,500 hrs) = 7,492,500	7,492,500	32,507,500
12/31/20	40,000,000	($1,665*6,000 hrs) = 9,990,000	17,482,500	22,517,500
12/31/21	40,000,000	($1,665*5,200 hrs) = 8,658,000	26,140,500	13,859,500
12/31/22	40,000,000	($1,665*4,300 hrs) = 7,159,500	33,300,000	6,700,000
12/31/23	40,000,000	($1,665*2,000 hrs) = 3,330,000	36,630,000	3,370,000
12/31/24	40,000,000	($1,665*2,000 hrs) = 3,330,000	39,960,000	40,000
Total		39,960,000

6) Depreciation rate using double declining balance = (1/Useful Life in years)*2

= (1/6 yrs)*2 = 0.333 i.e. 1/3

Depreciation Schedule using the Double Declining method (Amounts in $)

Date	Opening Book value (A)	Depreciation for the year (B = A*1/3)	Accumulated Depreciation (C)	Closing Book Value (A-C)
12/31/19	40,000,000	13,333,333	13,333,333	26,666,667
12/31/20	26,666,667	8,888,889	22,222,222	17,777,778
12/31/21	17,777,778	5,925,926	28,148,148	11,851,852
12/31/22	11,851,852	3,950,617	32,098,765	7,901,235
12/31/23	7,901,235	2,633,745	34,732,510	5,267,490
12/31/24	5,267,490	1,755,830	36,488,340	3,511,660
Total		36,488,340

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