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4) Depreciation per annum using straight line = (Cost - Residual Value)/Useful Life

= ($40,000,000 - $40,000)/6 years = $6,660,000 per year

Depreciation Schedule using the straight line method (Amounts in $)

Date	Asset Cost (A)	Depreciation for the year (B)	Accumulated Depreciation (C)	Book Value (A-C)
01/01/19	40,000,000			40,000,000
12/31/19	40,000,000	6,660,000	6,660,000	33,340,000
12/31/20	40,000,000	6,660,000	13,320,000	26,680,000
12/31/21	40,000,000	6,660,000	19,980,000	20,020,000
12/31/22	40,000,000	6,660,000	26,640,000	13,360,000
12/31/23	40,000,000	6,660,000	33,300,000	6,700,000
12/31/24	40,000,000	6,660,000	39,960,000	40,000
Total		39,960,000

5) Depreciation per hour = (Cost - Residual Value)/Useful Life in hours

= ($40,000,000 - $40,000)/24,000 hours = $1,665 per hour

Depreciation Schedule using the straight line method (Amounts in $)

Date	Asset Cost (A)	Depreciation for the year (B)	Accumulated Depreciation (C)	Book Value (A-C)
01/01/19	40,000,000			40,000,000
12/31/19	40,000,000	($1,665*4,500 hrs) = 7,492,500	7,492,500	32,507,500
12/31/20	40,000,000	($1,665*6,000 hrs) = 9,990,000	17,482,500	22,517,500
12/31/21	40,000,000	($1,665*5,200 hrs) = 8,658,000	26,140,500	13,859,500
12/31/22	40,000,000	($1,665*4,300 hrs) = 7,159,500	33,300,000	6,700,000
12/31/23	40,000,000	($1,665*2,000 hrs) = 3,330,000	36,630,000	3,370,000
12/31/24	40,000,000	($1,665*2,000 hrs) = 3,330,000	39,960,000	40,000
Total		39,960,000

6) Depreciation rate using double declining balance = (1/Useful Life in years)*2

= (1/6 yrs)*2 = 0.333 i.e. 1/3

Depreciation Schedule using the Double Declining method (Amounts in $)

Date	Opening Book value (A)	*Depreciation for the year (B = A1/3)**	Accumulated Depreciation (C)	Closing Book Value (A-C)
12/31/19	40,000,000	13,333,333	13,333,333	26,666,667
12/31/20	26,666,667	8,888,889	22,222,222	17,777,778
12/31/21	17,777,778	5,925,926	28,148,148	11,851,852
12/31/22	11,851,852	3,950,617	32,098,765	7,901,235
12/31/23	7,901,235	2,633,745	34,732,510	5,267,490
12/31/24	5,267,490	1,755,830	36,488,340	3,511,660
Total		36,488,340

A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome .

- June 12, 2021

Question: A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome . Answer: Step 1 PROGRAMING CODE: #include <stdio.h> int main() { int n, a, b, c, d, e; int digit = 0; printf( "Enter one 5 digit number: \n" ); scanf( "%d", &n ); a = n / 10000; b = n / 1000 % 10; c = n / 100 % 10; d = n / 10 % 10; e = n % 10; if ( a == e && b == d ) { printf( "Palindrome!\n" ); } if ( a != e || b != d ) { printf( "Not a palindrome.. :(\n" ); } return 0; } PROGRAM SCREENSHOT: Step 2

QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

- June 05, 2021

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- May 29, 2021

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A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome .

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