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Let the starting point from where Ruth starts her journey be the origin.
Then Ward is at (100 , 50) and Ruth's final position is (68 , -15).
Part A) So ward's displacement vector will be r = (68 - 100) i + (-15 - 50) j = -32 i - 65 j
displacement vector's horizontal component r x = - 32
displacement vector's horizontal component r y = - 65
Part B) magnitude = (32 2 + 65 2 ) = 72.44 m
Part C) Let be the angle the displacement vector forms with +ve x-axis.
= tan -1 (65/32) = 63.78 o
direction of Ward's displacement vector, measured clockwise from the negative y axis = 90 - = 26.21 o