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Answer:
Step 1 of 2
We have to calculate for the following reaction.
The reaction is:
First we write the ionic form of this reaction, and then this will be as:
Now, the entropy values of above ions are shown in the table below:
Step 2 of 2
So, the entropy change in the reaction will be:
Putting the values we get:
Hence, the value of is
for the reaction between silver nitrate with potassium chloride.