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E = 200 Gpa = 20 times 10^5 mpa I = 500 times 10^6 mm^4 Bending moment due to applied loading (moments are taken as positive when they cause tension in bottom, fiber) There moment Eqn: ML(l_L/I_L) + 2M_c[l_L/I_L + R_R/I_R] + M_R(l_R/I_R) = -6 A_r x_R/I_r R_R-6 A_L x_L/I_L l_L A_l, A_r: Are of bending moment diagram due to applied loads on left & right support respectively \r\n x_L, x_R: C.G of respective areas from left & right support respective for spam ABC A_L = 2/3 times 8 times 320 = 1706.7 A_R = 2/3 times 320 = 1706.7 x_1 = 4, x_R = 4 \r\n for span ABC A_l = 2/3 times 320 times 8 = 5120/3 = A_R x_L = x_R = 4 Using 3-moment theorm: therefore 0 + 2M_B(8/I + 8/2I) + M_c(8/2I) = -6 times 5120 times 4/3 times 8I-6 times 5120 times 4/3 times 8 times (2I) implies 24 M_B + 4M_C = -7680 6 M_B + M_c = -1920