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Question:


Bond Dissociation Energy


Suppose there is an element X which occurs naturally as X2(g).

X2(g) + 2O2(g) → X2O4(g)

X2O4 has a structure 

ΔHof of O(g) is 249 kJ/mol
ΔHof of X(g) is 478.5 kJ/mol
ΔHof of X2O4(g) is 9 kJ/mol
The X-X single bond energy is 120. kJ/mol

Use the above data to estimate the average  bond energy in X2O4.

Give your answer to the nearest 1 kJ/mol.


Answer:


Given data :

Reaction

X2(g) + 2O2(g) → X2O4(g)

Heat of dissociation.

ΔHof of O(g) is 249 kJ/mol

There 4 mole of oxygen atom as in the form of 2 mole of O 2 gas. Hence heat generated for formation of 4 mole of  O atom 

= 4 mole × 249 KJ / mole = 996 KJ

ΔHof of X(g) is 478.5 kJ/mol

There 2 mole of X atom as in the form of 1 mole of X 2 gas. Hence heat generated for formation of 2 mole of  X atom 

= 2 mole × 478.5 KJ / mole = 957 KJ

Hof of X2O4(g) is 9 kJ/mol

The X-X single bond energy is 120. kJ/mol

In the given product molecule there 1 X - X bond and 

4 X = O bond

Hof of X= O = ??

From the reaction we can say

Hof of X2O4 = { ( 2 × ΔHof of X(g) ) + ( 4 × ΔHof of O(g)) } - { ( ΔHof of X - X) + ( 4 × ΔHof of X= O ) }

Hof of X2O4 + { ( ΔHof of X - X) + ( 4 × ΔHof of X= O ) } =  { ( 2 × ΔHof of X(g) ) + ( 4 × ΔHof of O(g)) } 

Putting the values in equation.

9 KJ / mol + 120 KJ / mol + ( 4 × ΔHof of X= O ) = 957 KJ + 996 KJ 

129 KJ / mol + ( 4 × ΔHof of X= O ) = 1953 KJ

(4 × ΔHof of X= O )= 1953 KJ - 129 KJ / mole 

( ΔHof of X= O ) =( 1824 KJ / mole) / 4 = 456 KJ / mole

Average bond energy for the formation of X= O in X2O4 

= 456 KJ / mole

 

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