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Answer:


check out the solution.

------------------------------------------------

1.

CODE:

#include<stdio.h>
#include<string.h>

int main(int argc, char *argv[]) {
    // variable declaration
    char str[100];
    int i;
    
    // infinite while loop
    while(1)
    {
        // prompt user to enter input 
        printf("\nEnter the Input (9999 to quit) : ");
        // reads the input from console
        scanf("%[^\n]%*c",str);
    
        if(strcmp(str, "9999") == 0)    // EOF - indicates end of user input
            break;
        
        // check for the command line argument
        if(strcmp(argv[1], "--upper") == 0)
        {
            // loop through characters and convert accordingly
            for (i = 0; i < strlen(str); i++)
            {
                if(str[i] >= 'a' && str[i] <= 'z' && str[i] != ' ')
                {
                    str[i] = str[i] - 32;
                }
                    
            }
            // display the converted string
            printf("%s", str);
        }
        else if(strcmp(argv[1], "--lower") == 0)
        {
            for (i = 0; i < strlen(str); i++)
            {
                if(str[i] >= 'A' && str[i] <= 'Z' && str[i] != ' ')
                    str[i] = str[i] + 32;
            }
            printf("%s", str);
        }
        else if(strcmp(argv[1], "--swap") == 0)
        {
            for (i = 0; i < strlen(str); i++)
            {
                if(str[i] >= 'A' && str[i] <= 'Z' && str[i] != ' ')
                    str[i] = str[i] + 32;
                else if(str[i] >= 'a' && str[i] <= 'z' && str[i] != ' ')
                    str[i] = str[i] - 32;
            }
            printf("%s", str);
        }
        else // print the message appropriately if invalid argument
            printf("\n\nInvalid command line argument!!!");
        // if-elseif ends
            
    } // infinite while loop ends
        
} // main ends

------------------------------------------------------------------------------------------

------------------------------------------------------

OUTPUT :

1. command line argument : --upper

2. command line argument : --lower

 

3. command line argument : --swap

---------------------------------------------------------------

2.

CODE:

#include<stdio.h>
#include<string.h>

int main(int argc, char *argv[]) {
    // variable declaration
    char str[100];
    int i, cnt = 0;
    
    // infinite while loop
    while(1)
    {
        // prompt user to enter input 
        printf("\nEnter the Input (9999 to quit) : ");
        // reads the input from console
        scanf("%[^\n]%*c",str);
    
        if(strcmp(str, "9999") == 0)    // EOF - indicates end of user input
            break;
        
        // loop through characters and convert accordingly
        for (i = 0; i < strlen(str); i++)
        {
            // check if char is in between 0 and 9 and count them if any
            if(str[i] >= '0' && str[i] <= '9')
            {
                cnt++;
            }
                
        }
    } // infinite while loop ends
    
    // when input reaches EOF - display the count of digits
    printf("%d digits", cnt);
        
} // main ends

--------------------------------------------------------------

------------------------------------------------------------------------------

OUTPUT :

1.

2.

3.

==================================================

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QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

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