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resource-allocation graph -> how to resource allocated for graph.

set of vertices(V)->

1. set of process {P 1 ,P 2 ,P 3, P 4 ,P 5.... P n }

2. set of resources{R 1 ,R 2 ,R 3 ,R 4 ,R 5 ....R n }

set of edges->

1. P i 1 R j (request edge)

2. R j 1 P i (assignment edge)

resource type= \square (squre)

process type= \circ (circle)

in above question resources allocation graph is

process P = {P 1 ,P 2 ,P 3, P 4 ,P 5 }

resources R= {R 1 ,R 2 ,R 3 ,R 4 ,R 5 }

RE Ri P pi le Ru RE Rs xesomoly - allocation goapb . CS Scanned with CamScanner

no cycle are create so not go to deadlock process.

wait for graph -> use only process

if P 1 is waiting for R 3 and R 3 is assigned for P 4 then we draw only P 1 1 P 4 .

if P 2 is waiting for R 3 and R 3 is assigned for P 4 then we draw only P 2 1 P 4 .

etc....

no cycle are create so not go deadlock and say system is safe state.

ST

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A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome .

Question: A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome . Answer: Step 1 PROGRAMING CODE:   #include <stdio.h> int main() {   int n, a, b, c, d, e;   int digit = 0;   printf( "Enter one 5 digit number: \n" );   scanf( "%d", &n );   a = n / 10000;   b = n / 1000 % 10;   c = n / 100 % 10;   d = n / 10 % 10;   e = n % 10;   if ( a == e && b == d ) {     printf( "Palindrome!\n" );   }   if ( a != e || b != d ) {     printf( "Not a palindrome.. :(\n" );   }   return 0; } PROGRAM SCREENSHOT: Step 2

QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

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