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Incline angel of both the inclines \theta = tan-13/4 = 36.87 o

Let tension in cord connected to mass 300 lb be T 1 and tnbsion in cord connected to 400 lb be T 2

As pulleys are massless therefore by Newtons second law on left pulley

2T 2 - T 1 = 0

So T 1 = 2T 2

Let acceleleration in block A be a A and acceleration in block B be a B .

We assume block B is going down and block A is going up.

Friction force on block A

F fA = \mu m A g Cos \theta = 0.2 X 300 X 32.2 X Cos 36.87 = 1545.6 lbs

Applying Netons second law on block A

T 1 - m A g Sin \theta - F fA = m A a A

So 2T 2 - 300 X 32.2 X Sin 36.87 - 1545.6 = 300 a A

So  2T 2 - 7341.6 = 300 a A

So T 2 - 150 a A = 3670.8 ----------------------(1)

Friction force on block B

F fB = \mu m A g Cos \theta = 0.2 X 400 X 32.2 X Cos 36.87 = 2060.8 lbs

Applying Netons second law on block B

T 2 - m B g Sin \theta + F fA = m B a B

So T 2 - 400 X 32.2 X Sin 36.87 + 2060.8 = 400 a B

So T 2 - 5667.2 = 400 a B

So T 2 - 400 a B = 5667.2 ----------------------(2)

Also as cord connected with block B will move double the distance as moved by block A

a B = 2 a A

Putting value of a B is equation (2)

T 2 - 800 a A = 5667.2 -------------------(1)

Sustracting equation (3) from (2)

650 a A = -1996,4

So  a A = -3.1 ft /s 2

a B = 2a A = - 6.2 ft /s 2

Minus sign indicates that block B will move upward.

So acceleration of block B =  6.2 ft /s 2 (upward )

Putting vale of a B in equation (2)

T 2 - 400 X (-6.2) = 5667.2

So T 2 = 3187.2 lb

So acceleration of block B =  6.2 ft /s 2 (upward )

Tension is cord attached to B , T 2 = 3187.2 lb

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A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome .

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