Encrypting your link and protect the link from viruses, malware, thief, etc! Made your link safe to visit.

 a. Portfolio expected return is

= weight in big toys *return on big toys + weight in chemical industries*return on chemical industries

=0.62*0.10 + 0.38*0.12

=0.062 + 0.0456

=10.76%

portfolio standard deviation :

= root over of [ (w1)^2* variance of big toys + (w2)^2*variance of chemical industries + 2 *W1*W2*CORRELATION BETWEEN BIG TOYS AND CHEMICAL INDUSTRIES*standard deviation of big toys*standard deviation of chemical industries]

=(0.62)^2*(0.218)^2 + (0.38)^2* (0.277)^2 + 2 * 62*0.38*0.31*0.218*0.277

=0.0183+ 0.0111 + 0.0088

=19.55%

b. Portfolio expected return will be the same = 10.76%

The standard deviation will be :

root over of [(0.62)^2*(0.218)^2 + (0.38)^2*(0.277)^2 + 2 *0.62*0.38*0.81*0.218*0.277]

=0.0183 + 0.0111 + 0.0230

=22.9%

c. the lower the correlation, between the assets the higher will be the benefits and lower will be the standard deviation.

The difference is due to the, the higher correlation, which resulted in a higher standard deviation,

ST

Search This Blog

Labels

Report Abuse

A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome .

Question: A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome . Answer: Step 1 PROGRAMING CODE:   #include <stdio.h> int main() {   int n, a, b, c, d, e;   int digit = 0;   printf( "Enter one 5 digit number: \n" );   scanf( "%d", &n );   a = n / 10000;   b = n / 1000 % 10;   c = n / 100 % 10;   d = n / 10 % 10;   e = n % 10;   if ( a == e && b == d ) {     printf( "Palindrome!\n" );   }   if ( a != e || b != d ) {     printf( "Not a palindrome.. :(\n" );   }   return 0; } PROGRAM SCREENSHOT: Step 2

QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

  Question: Show transcribed image text Answer:

Contributors