Use the C programming language and NOT C++ programmming language to solve the following problems:
Question:
Use the C programming language and NOT C++ programmming language to solve the following problems:
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Answer:
#include <stdio.h>
int squareof(int n){
return n*n;
}
int cubeof(int n){
return n*n*n;
}
int main()
{
int a;
printf("factorial of odd numbers:\n")
for(int i=14;i>=1;i--){
int fact=1;
if(i%2!=0){
for(int j=1;j<=i;j++){
fact=fact*j;
}
printf("%d",fact);
}
}
printf("\nfactorial of even numbers:\n")
for(int j=1;j<=14;j++){
int fact=1;
if(i%2==0){
for(int j=1;j<=i;j++){
fact=fact*j;
}
printf("%d",fact);
}}
printf("\nsquares of all numbers between -12 to 12:\n");
for(int i=12;i>=-12;i--){
printf("%d \t",squareof(i));
}
printf("\n Cubes of numbers between -12 to 12:");
for(int i=-12;i<=12;i++){
printf("%d \t",cubesof(i));
}
printf("\n 5th power of all numbers between -9 to 9");
for(int i=-9;i<=9;i++){
int a=squareof(i)*cubeof(i);
printf("%d\t",a);
}
return 0;
}
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#include <stdio.h>
int squareof(int n){
return n*n;
}
int cubeof(int n){
return n*n*n;
}
int main()
{
int a;
printf("factorial of odd numbers:\n")
int i=14;
while(i>=1){
int j=1;
int fact=1;
if(i%2!=0){
while(j<=i){
fact=fact*j;
}
j++
printf("%d",fact);
}
i--;
}
printf("\nfactorial of even numbers:\n")
int j=1;
while(j<=14){
int fact=1;
if(j%2==0){
while(i<=j){
fact=fact*j;
}
i++
printf("%d",fact);
}
j++;
}
printf("\nsquares of all numbers between -12 to 12:\n");
for(int i=12;i>=-12;i--){
printf("%d \t",squareof(i));
}
printf("\n Cubes of numbers between -12 to 12:");
for(int i=-12;i<=12;i++){
printf("%d \t",cubesof(i));
}
printf("\n 5th power of all numbers between -9 to 9");
for(int i=-9;i<=9;i++){
int a=squareof(i)*cubeof(i);
printf("%d\t",a);
}
return 0;
}
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