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Use the C programming language and NOT C++ programmming language to solve the following problems:

Question:


Use the C programming language and NOT C++ programmming language to solve the following problems:Using the nested for loops, find the factorials of

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Answer:


#include <stdio.h>

int squareof(int n){
return n*n;
}
int cubeof(int n){
return n*n*n;
}
int main()
{
int a;
printf("factorial of odd numbers:\n")
for(int i=14;i>=1;i--){

int fact=1;
if(i%2!=0){
for(int j=1;j<=i;j++){

fact=fact*j;

}

printf("%d",fact);
}

}
printf("\nfactorial of even numbers:\n")
for(int j=1;j<=14;j++){

int fact=1;
if(i%2==0){
for(int j=1;j<=i;j++){

fact=fact*j;

}

printf("%d",fact);

}}
printf("\nsquares of all numbers between -12 to 12:\n");
for(int i=12;i>=-12;i--){
printf("%d \t",squareof(i));
}
printf("\n Cubes of numbers between -12 to 12:");
for(int i=-12;i<=12;i++){
printf("%d \t",cubesof(i));
}
printf("\n 5th power of all numbers between -9 to 9");
for(int i=-9;i<=9;i++){
int a=squareof(i)*cubeof(i);
printf("%d\t",a);
}
return 0;
}

---------------------------------------------------------------------------------------------------------------------------------------------------

#include <stdio.h>

int squareof(int n){
return n*n;
}
int cubeof(int n){
return n*n*n;
}
int main()
{
int a;
printf("factorial of odd numbers:\n")
int i=14;
while(i>=1){
int j=1;
int fact=1;
if(i%2!=0){
while(j<=i){

fact=fact*j;

}
j++
printf("%d",fact);
}
i--;
}


printf("\nfactorial of even numbers:\n")
int j=1;
while(j<=14){

int fact=1;
if(j%2==0){
while(i<=j){

fact=fact*j;

}
i++
printf("%d",fact);

}
j++;
}
printf("\nsquares of all numbers between -12 to 12:\n");
for(int i=12;i>=-12;i--){
printf("%d \t",squareof(i));
}
printf("\n Cubes of numbers between -12 to 12:");
for(int i=-12;i<=12;i++){
printf("%d \t",cubesof(i));
}
printf("\n 5th power of all numbers between -9 to 9");
for(int i=-9;i<=9;i++){
int a=squareof(i)*cubeof(i);
printf("%d\t",a);
}
return 0;
}

---------------------------------------------------------------------------------------------------------------------------------------------------

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QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

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SERVER DISCORD FREE CHEGG, COURSEHERO, BARTLEBY https://discord.gg/eGMtZaqSZP https://www.coursehero.com/tutors-problems/Environmental-Science/29241920-Compare-and-contrast-chemical-oxidation-and-chemical-reduction-technol/?justUnlocked=1 ad Oxidation-reduction reaction , also called redox reaction , any chemical reaction in which the oxidation number of a participating chemical species changes. The term covers a large and diverse body of processes. Many oxidation-reduction reactions are as common and familiar as fire, the rusting and dissolution of metals, the browning of fruit, and respiration and photosynthesis—basic life functions.  Oxidation is the  gain  of oxygen. Reduction is the  loss  of oxygen. Most oxidation-reduction (redox) processes involve the transfer of oxygen atoms, hydrogen atoms, or electrons, with all three processes sharing two important characteristics: (1) they are coupled in any oxidation reaction a reciprocal reduction occu...

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