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The principal component of LPG is butane, C 4 H 10 (g) . If combustion of 1 mole of butane produces 126 kJ of heat, how much heat can be generated by complete combustion of one 11.0-kg gas tank?

 

Question:


The principal component of LPG is butane, C 4 H 10 (g) . If combustion of 1 mole of butane produces 126 kJ of heat, how much heat can be generated by complete combustion of one 11.0-kg gas tank?

Answer:


Cahio +1302 74602+ 5 H20) He=-126 KJ/mol 1 mole (8589) C4H10 126KI 110 Kg (11x1038) C4H10 → ? (x) 11X103 x126 58 = 23.896x103

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Question: A 250-V, 4-pole, wave-wound d.c. series motor has 782 conductors on itsarmature. It has armature and series field resistance of 0.75 ohm. The motor takesa current of 40 A. Estimate its speed and gross torque developed if it has a flux per pole of 25 mWb Answer: Step 1 Step 2 Step 3
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