Link BD consists of a single bar 30 mm wide and 12 mm thick. Knowing that each pin has a10 mm diameter, determine the maximum value of the average normal stress in the link BD if θ = 15 degrees.

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Textbook Solution:

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Answer:

To determine

a$a$

Total force that resist the motion of car, boat and trailer.

Answer

Total force =910N$=910N$

Explanation

Given:

Mass of car M=1100Kg$M=1100Kg$
Force exerted by car on road Fcar=1900N$F_{car}=1900N$
Acceleration a=0.550ms2$a=0.550\frac{m}{s^2}$

Mass of Boat & Trailer MBT=700Kg$M_{BT}=700Kg$

Formula used:

Using Newton's Second Law of motion,

  Fnet=ma$F_{net}=ma$

Calculation:

Let Resistive force is R
Total mass m =(1100+700)Kg$=(1100+700)Kg$

=1800Kg$=1800Kg$
Driving force by car Fcar=1900N$F_{car}=1900N$

By Applying Newton's Second Law of motion,

Fcar−R=ma$F_{car}-R=ma$

  1900−R=(1800)(0.550)$1900-R=(1800)(0.550)$

  1900−R=9901900−990=R910N=R$\begin{array}{l}1900-R=990\\ 1900-990=R\\ 910N=R\end{array}$

Conclusion:

Total resistive force =910N