Encrypting your link and protect the link from viruses, malware, thief, etc! Made your link safe to visit.

 

Textbook Solution:



Answer:


To determine

a

Total force that resist the motion of car, boat and trailer.

Answer

Total force =910N

Explanation

Given:

Mass of car M=1100Kg
Force exerted by car on road Fcar=1900N
Acceleration a=0.550ms2

Mass of Boat & Trailer MBT=700Kg

Formula used:

Using Newton's Second Law of motion,

  Fnet=ma

Calculation:

Let Resistive force is R
Total mass m =(1100+700)Kg

=1800Kg
Driving force by car Fcar=1900N

By Applying Newton's Second Law of motion,

College Physics, Chapter 4, Problem 29PE FcarR=ma

  1900R=(1800)(0.550)

  1900R=9901900990=R910N=R

Conclusion:

Total resistive force 

ST

Search This Blog

Labels

Report Abuse

Question: A 250-V, 4-pole, wave-wound d.c. series motor has 782 conductors on itsarmature. It has armature and series field resistance of 0.75 ohm. The motor takesa current of 40 A. Estimate its speed and gross torque developed if it has a flux per pole of 25 mWb Answer: Step 1 Mechanical Engineering homework question answer, step 1, image 1 Mechanical Engineering homework question answer, step 1, image 2 Step 2 Mechanical Engineering homework question answer, step 2, image 1 Step 3 Mechanical Engineering homework question answer, step 3, image 1

Question: A 250-V, 4-pole, wave-wound d.c. series motor has 782 conductors on itsarmature. It has armature and series field resistance of 0.75 ohm. The motor takesa current of 40 A. Estimate its speed and gross torque developed if it has a flux per pole of 25 mWb Answer: Step 1 Step 2 Step 3

QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

  Question: Show transcribed image text Answer:

Contributors