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Question:


Write a program that creates a Date object, sets its elapsed
time to 10000, 100000, 1000000, 10000000, 100000000, 1000000000,
10000000000, and 100000000000, and displays the date and time using the
toString() method, respectively.


Answer:


Step 1

A Java program is as follows,

File name: “Sample.java”

//Create a class

public class Sample {

      //Define the main() method

      public static void main(String[] args) {

            //Create Date object

            java.util.Date d = new java.util.Date();

            //Initialize the array

            long[] tms = new long[] {10000, 100000, 1000000, 10000000,

                        100000000, 1000000000, 10000000000L, 100000000000L};

            //Create a loop

            for (int i = 0; i < tms.length; i++) {

                  //Call the method

                  d.setTime(tms[i]);

                  //Print the date and time

                  System.out.println(d.toString());

            }    

      }

}

Step 2

Computer Science homework question answer, step 2, image 1

Step 3

Computer Science homework question answer, step 3, image 1

ST

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A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome .

Question: A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome . Answer: Step 1 PROGRAMING CODE:   #include <stdio.h> int main() {   int n, a, b, c, d, e;   int digit = 0;   printf( "Enter one 5 digit number: \n" );   scanf( "%d", &n );   a = n / 10000;   b = n / 1000 % 10;   c = n / 100 % 10;   d = n / 10 % 10;   e = n % 10;   if ( a == e && b == d ) {     printf( "Palindrome!\n" );   }   if ( a != e || b != d ) {     printf( "Not a palindrome.. :(\n" );   }   return 0; } PROGRAM SCREENSHOT: Step 2

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