Link BD consists of a single bar 30 mm wide and 12 mm thick. Knowing that each pin has a10 mm diameter, determine the maximum value of the average normal stress in the link BD if θ = 15 degrees.

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Question:

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Explanation

Given Information:

  VCC=3.3 V, RE=500 Ω , RC=4 kΩ, R1=85 kΩ, R2=35 kΩ and β=150$V_{CC}=3.3\text{ V, }{R}_E\text{=500 }\Omega \text{ , }{R}_C\text{=4 k}\Omega ,R_1\text{=85 k}\Omega ,R_2\text{=35 k}\Omega \text{ and }\beta =150$

Calculation:

Use the equations of Thevenin voltage and Thevenin resistance to solve the problem. The figure below shows the original circuit and the

  

Calculation:

Thevenin resistance is

  RTH=(R1R2R1+R2)=(85×3585+35) kΩ$R_{TH}=\left(\frac{R_1{R}_2}{R_1+R_2}\right)=\left(\frac{85\times 35}{85+35}\right)\text{ k}\Omega$

  RTH=24.8 kΩ$R_{TH}=24.8\text{ k}\Omega$

Thevenin voltage is

  VTH=(R2R1+R2)VCC=(3585+35)3.3 V$V_{TH}=\left(\frac{R_2}{R_1+R_2}\right)V_{CC}=\left(\frac{35}{85+35}\right)3.3\text{ V}$

  VTH=0.9625 V