QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

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 Question

I need the source code in Java

1) find the index of the largest value of an array.

2) display the index of the largest value of an array.

3) Sum the total of the largest value of an array

For example the car array is = {2,3,0,3}

[0] = 2 belongs to suzuki

[1] = 3 belongs to honda

[2] = 0 belong to toyota

[3] = 3 belongs to hyundai

I need the solution in Java to find the largest value which is 3. so if 2 of the elements in the array is the largest, I need to display both

The sample output should be as this format

The largest value is :

honda = 3

hyundai = 3

Sum of the total cars = 6

Solution

Introduction

Use an array to store the number of cars and another array to store respective cars

Main.java

public class Main
{
 public static void main(String[] args) 
 {
  int car[]={2,3,0,3};        //initialize cars array 
  String brand[]={"suzuki","honda","toyota","hyudai"};    //initialize brands array
  
  int maximum=car[0]; //assign first car as maximum 
  
  for(int i=1; i<4; i++){ //i from 1 to 3
      if(maximum<car[i])      //if larger element is found 
          maximum=car[i];         //replace maximum
  } 
  
  int sum=0;     //initialize sum to 0
  for(int i=0;i<4;i++){   //i from 0 to 3
      if(car[i]==maximum){    //if car is same as maximum
          System.out.println(brand[i]+" = "+car[i]);  //print brand and car
          sum=sum+car[i];                             //add car to sum 
      }
  }
  System.out.println("Sum of the total cars = "+sum); //print sum finally
 }
}

Output