Question: A 250-V, 4-pole, wave-wound d.c. series motor has 782 conductors on itsarmature. It has armature and series field resistance of 0.75 ohm. The motor takesa current of 40 A. Estimate its speed and gross torque developed if it has a flux per pole of 25 mWb Answer: Step 1 Mechanical Engineering homework question answer, step 1, image 1 Mechanical Engineering homework question answer, step 1, image 2 Step 2 Mechanical Engineering homework question answer, step 2, image 1 Step 3 Mechanical Engineering homework question answer, step 3, image 1

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 Question

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Solution

Step 1

The complex power in an AC system is defined as the product of rms value of applied voltage and complex conjugate of the resulting current in the circuit.

S=VI* = P + jQ

Where,

I*=conjugate of current

The real part of the complex power represents the active power/ true power. Active power in a circuit is the actual power consumed in the circuit. It is also given as the product of rms voltage and current and cosine of power factor angle.

Mathematically, it is given as

P = VI cosϕ

The imaginary part of the complex power gives the reactive power, reactive power in the circuit flows back and forth in the circuit. Reactive power in the circuit is defined as the product of rms values of voltage and current and sine of the angle between voltage and current.

Mathematically, it is given as:

Q = VI sinϕ

Step 2

In the above given circuit, Three phase power measurement is done with the help of two wattmeter method.

The formula for two wattmeter connection is given as:

Now wattmeter readings of A and B is given as:

Therefore,

W_A = -598 W

and W_B = 1633 W

 

Calculation of total power:

Therefore, total power from summation of wattmeter reading and from calculation P_3-phase=3*P_1-phase is same and given as 1035 W