QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

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Question:

A hydraulic lift is to be used to lift a 550 kg weight, the piston–cylinder of the hydraulic lift contains oil at a pressure of 580 kPa. The piston has a mass of 6 kg and a diameter of 12 cm. In this case the local atmospheric pressure is a. 100 kPa b. 95.7 kPa c. 98 kPa d. None of these e. 96.3 kPa f. 97.3 kPa

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Answer:

Step 1

Given:

• Mass of the body to lifted (M)=550kg
• Mass of the piston (m)=6kg
• Diameter of the piston (D)=12cm
• Pressure inside the piston cylinder (P)=580kPa

Step 2

Solution:

The pressure inside the piston cylinder will be equal to the sum of atmospheric pressure and pressure due to the weight of the object and piston,

Therefore, local atmospheric pressure is 98kPa-option C is the answer.