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Question:


Computer A has 145 MB data to send on a network and transmits the data in a burst @ 20 Mbps. The maximum transmission rate across routers in the network is 10 Mbps. If Computer A's transmission is shaped using a leaky bucket then what will be the bucket size to make sure that no data is discarded?

Answer:


20 Mb → 1 sec

(145MB *8) Mb → ( time for computer to transmit data)??

time for computer to transmit data = total bits / max trans rate

= (145 MB * 8 bits/byte) / 20 Mbps

= 1160Mb / 20 Mb/s

= 58 s

10 Mb → 1 sec

actual data sent on network ?? → 58 sec

actual data sent on network in 58 s = network rate * 58 s

= 10 Mb/s * 58s

= 580 Mbits = 72.5 Mbytes

bucket size = 145 MB - 72.5 MB = 72.5MB(or 580Mb)

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  Introduction To find incremental revenue and cost, we subtract Current revenue and cost from Projected revenue and cost. Answer Current Situation Projected Sales and Profit Incremental Revenues and Costs Total Revenue Php1,500,000 Php1,800,000 + Php3000,000 Variable Cost 575,000 425,000 - Php 332,000 Direct Fixed Costs 625,000 700,000 + Php 75,000 Indirect Fixed Costs 100,000 100,000 No change Profit Php 200,000 Php 575,000 + Php 375,000 Profit increases by Php 375,000, thus a new camera and coffee maker must be purchased.

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