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Question:


Computer A has 145 MB data to send on a network and transmits the data in a burst @ 20 Mbps. The maximum transmission rate across routers in the network is 10 Mbps. If Computer A's transmission is shaped using a leaky bucket then what will be the bucket size to make sure that no data is discarded?


Answer:


20 Mb → 1 sec

(145MB *8) Mb → ( time for computer to transmit data)??

time for computer to transmit data = total bits / max trans rate

= (145 MB * 8 bits/byte) / 20 Mbps

= 1160Mb / 20 Mb/s

= 58 s

10 Mb → 1 sec

actual data sent on network ?? → 58 sec

actual data sent on network in 58 s = network rate * 58 s

= 10 Mb/s * 58s

= 580 Mbits = 72.5 Mbytes

bucket size = 145 MB - 72.5 MB = 72.5MB(or 580Mb)

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