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Question:


Answer:


Step 1

The free body diagram of the section ADEB is,

Mechanical Engineering homework question answer, step 1, image 1

Here, P is the effective loading due to the UDL. H and V are the subscript for the horizontal and vertical reaction at A respectively.

Step 2

Calculate the value of effective loading due to the UDL, P,

Mechanical Engineering homework question answer, step 2, image 1

Consider the angle B as θ and apply the condition for the equilibrium of moment about support A.

Mechanical Engineering homework question answer, step 2, image 2

Step 3

Apply the condition for the equilibrium of forces along the vertical direction.

Mechanical Engineering homework question answer, step 3, image 1

Step 4

Similarly, apply the condition for the equilibrium of forces along the horizontal direction.

Mechanical Engineering homework question answer, step 4, image 1

Step 5

Consider the FBD of the section AD of the beam,

Mechanical Engineering homework question answer, step 5, image 1

Calculate the effective load due to UDL, PAD  acting on AD,

Mechanical Engineering homework question answer, step 5, image 2

Step 6

Apply the condition for the equilibrium of forces along the vertical direction for the section AD.

Mechanical Engineering homework question answer, step 6, image 1

This the vertical reaction at point D.

Step 7

Apply the condition for the equilibrium of forces along the horizontal direction for the section AD.

Mechanical Engineering homework question answer, step 7, image 1

This the horizontal reaction at point D.

Step 8

Now, apply the condition for the equilibrium of moment about point D.

Mechanical Engineering homework question answer, step 8, image 1

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QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

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SERVER DISCORD FREE CHEGG, COURSEHERO, BARTLEBY https://discord.gg/eGMtZaqSZP https://www.coursehero.com/tutors-problems/Environmental-Science/29241920-Compare-and-contrast-chemical-oxidation-and-chemical-reduction-technol/?justUnlocked=1 ad Oxidation-reduction reaction , also called redox reaction , any chemical reaction in which the oxidation number of a participating chemical species changes. The term covers a large and diverse body of processes. Many oxidation-reduction reactions are as common and familiar as fire, the rusting and dissolution of metals, the browning of fruit, and respiration and photosynthesis—basic life functions.  Oxidation is the  gain  of oxygen. Reduction is the  loss  of oxygen. Most oxidation-reduction (redox) processes involve the transfer of oxygen atoms, hydrogen atoms, or electrons, with all three processes sharing two important characteristics: (1) they are coupled in any oxidation reaction a reciprocal reduction occu...

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