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Question:

Answer:
For a graph to have an Euler circuit it should have 0 verticies of odd degree.
If a graph has any vertices of odd degree, then it cannot have an Euler circuit. So checking for the same in the given graph. We find that vertex 'f' and vertex 'c' have odd degrees. As there are 3 edges connected to both the verticies.
For a graph to have Euler Path the number of odd verticies should be not more than 2.
I f a graph has more than 2 odd verticies then it cannot be have an Euler Path. But as here it has just 2 odd verticies so it can have an Euler path. It can have more than one Euler Path.
One such Euler Path would be: fbafecbdeadc
