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For the next three items, consider a red laser light traveling in a crystal glass at a speed of 1.33x108 m/s with electric field vector E(y,t) = (8.00 N/C)(+î) sin(-(9.93 x 106 rad/m)y + wt]. 4. Freak! What is the frequency of the light? A. 2.10 x 1014 Hz B. 4.74 x 1014 Hz C. 1.32 x 1015 Hz D. 8.30 x 1015 Hz 5. Dear Prop. What is its direction of propagation? A. along +y-axis B. along -y-axis C. along +z-axis D. along - z-axis 6. Electric Fan. What is its corresponding electric field vector? A. B(y,t) = (6.02 x 10-8 T)(+î) sin((9.93 x 106 rad/m)y – wt] B. B(y,t) = (6.02 x 10-8 T)(-i) sin((9.93 x 106 rad/m)y - wt] C. B(y,t) = (6.02 x 10-8 T)(+î) cos[(9.93 x 106 rad/m)y - wt] D. B(y,t) = (6.02 x 10-8 T)(-i) cos((9.93 x 106 rad/m)y-wt]

 

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For the next three items, consider a red laser light traveling in a crystal glass at a speed of 1.33x108 m/s with electric fi

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Given 1:33 x 188 mis 4 Eo=8.000/ K - 29 99.3x108 radim 는 아 w: KN = 9.93 X 10 x 9.93 *108*1:33x108 w= 1.32 nios his f=w 1.325 it 하 E= E. Sinc-ky twt) represents direction of propagation ty-akis Answer: option A A 6 E. 2 2 1) ws B. - Eo = 6:02x008 11Propagation of E.M Wave along no Ê xß + i =Ê x ſ = Ã x (?) :. În ( :. Bly,t) = Bo (-ê) Sin (-ky + wt) Bo (-?) (- Sin (ky + wt:: BC&st)= 602 x Tots (+1) sin(9.933 oby-wr) Answer: option: B B

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A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome .

Question: A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome . Answer: Step 1 PROGRAMING CODE:   #include <stdio.h> int main() {   int n, a, b, c, d, e;   int digit = 0;   printf( "Enter one 5 digit number: \n" );   scanf( "%d", &n );   a = n / 10000;   b = n / 1000 % 10;   c = n / 100 % 10;   d = n / 10 % 10;   e = n % 10;   if ( a == e && b == d ) {     printf( "Palindrome!\n" );   }   if ( a != e || b != d ) {     printf( "Not a palindrome.. :(\n" );   }   return 0; } PROGRAM SCREENSHOT: Step 2

QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

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