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Compute the physical address for the specified operand in each of the following instructions from

 

Question:

  1. Compute the physical address for the specified operand in each of the following instructions from previous
    problem. The register contents and variables are as follows : (CS) = 0A0016, (DS) = 0B0016, (SI) =
    010016, (DI) = 020016 and (BX) = 030016.
    a) Destination operand of the instruction in (c)
    b) Source operand of the instruction in (d)
    c) Destination operand of the instruction in (e)
    d) Destination operand of the instruction in (f)
    e) Destination operand of the instruction in (g)
Compute the physical address for the specified operand in each of the following instructions from previousproblem. The register contents and variables are as follows : (CS) = 0A0016, (DS) = 0B0016, (SI) =010016, (DI) = 020016 and (BX) = 030016.a) Destination operand of the instruction in (c)b) Source operand of the instruction in (d)c) Destination operand of the instruction in (e)d) Destination operand of the instruction in (f)e) Destination operand of the instruction in (g)

Step 1 Introduction to physical address

Physical Address identifies a physical location of required data in a memory. The user never directly deals with the physical address but can access by its corresponding logical address. The user program generates the logical address and thinks that the program is running in this logical address but the program needs physical memory for its execution, therefore, the logical address must be mapped to the physical address by MMU before they are used. The term Physical Address Space is used for all physical addresses corresponding to the logical addresses in a Logical address space.

Step 2 Solution

The correct answer is option (a) Destination operand of the instruction in (c)

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QUESTION 6 (a) The bar shown in Figure Q2(a) is subjected to tensile load of 150 Kn. If the stress in the middle portions is limited to 160 N/mm², determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is to be 0.25 mm. E E = 2.0 + 105N/mm². (12 marks) 150 KN 10 cm DIA 10 cm DIA 150 KN 45 cm Figure Q6(a) (b) A brass bar, having cross-section area of 900 mm², is subjected to axial forces as shown in Figure Q2(b), in which AB = 0.6 m, BC = 0.8 m, and CD = 1.0 m. Find the total elongation of the bar. E = 1.0 + 105N/mm2 . (8 marks) Page 4 of 5 B D 40 KN 70 KN 20 KN 10 KN Figure Q6(b) (TOTAL = 20 MARKS)

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Question: A 250-V, 4-pole, wave-wound d.c. series motor has 782 conductors on itsarmature. It has armature and series field resistance of 0.75 ohm. The motor takesa current of 40 A. Estimate its speed and gross torque developed if it has a flux per pole of 25 mWb Answer: Step 1 Mechanical Engineering homework question answer, step 1, image 1 Mechanical Engineering homework question answer, step 1, image 2 Step 2 Mechanical Engineering homework question answer, step 2, image 1 Step 3 Mechanical Engineering homework question answer, step 3, image 1

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Question: A 250-V, 4-pole, wave-wound d.c. series motor has 782 conductors on itsarmature. It has armature and series field resistance of 0.75 ohm. The motor takesa current of 40 A. Estimate its speed and gross torque developed if it has a flux per pole of 25 mWb Answer: Step 1 Step 2 Step 3
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