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C++ PROGRAM

Textbook Solution:



Answer:


Program Plan Intro

Program plan:

  • Declare the variable number of integer type.
  • The cout statement is used to prompt a message to user and display output.
  • The cin statement is used to take an input from user.

Program description:

The following program will take an input from user and display its integer output.

Program Explanation

Program

//header file included
#include<iostream>
//namespace included
usingnamespace std;
//main function
intmain()
{
//Declare variable number of int type
int number;
//cout statement
cout<<"Enter a number:"<<endl;
//cin statement
cin>>number;
//display output
cout<<number;
//exiting from program
return 0;
}

Explanation:

In the above program, inputted number from a user using cin statement. Displayed the inputted number immediately using cout statement.

Observed output:-

if inputted number is of integer type then displayed output is also the same number.

if inputted number is of double-precision type then displayed output is also only the integer part of number.

if inputted number is of character type then displayed output is 0.

Sample Output:

  C++ for Engineers and Scientists, Chapter 3.4, Problem 12E , additional homework tip  1

  C++ for Engineers and Scientists, Chapter 3.4, Problem 12E , additional homework tip  2

  C++ for Engineers and Scientists, Chapter 3.4, Problem 12E , additional homework tip  3

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A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome .

Question: A palindrome is a number or a text phrase that reads the same backwards as forwards. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554 and 11611. Write a C++ program that reads in a five-digit integer and determines whether it is a palindrome . Answer: Step 1 PROGRAMING CODE:   #include <stdio.h> int main() {   int n, a, b, c, d, e;   int digit = 0;   printf( "Enter one 5 digit number: \n" );   scanf( "%d", &n );   a = n / 10000;   b = n / 1000 % 10;   c = n / 100 % 10;   d = n / 10 % 10;   e = n % 10;   if ( a == e && b == d ) {     printf( "Palindrome!\n" );   }   if ( a != e || b != d ) {     printf( "Not a palindrome.. :(\n" );   }   return 0; } PROGRAM SCREENSHOT: Step 2

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